b^2+5b-50=

Solution for b^2+5b-50= equation:

Simplifying
b2 + 5b + -50 = 0

Reorder the terms:
-50 + 5b + b2 = 0

Solving
-50 + 5b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-10 + -1b)(5 + -1b) = 0

Subproblem 1
Set the factor '(-10 + -1b)' equal to zero and attempt to solve:

Simplifying
-10 + -1b = 0

Solving
-10 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1b = 0 + 10
-1b = 0 + 10

Combine like terms: 0 + 10 = 10
-1b = 10

Divide each side by '-1'.
b = -10

Simplifying
b = -10
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {-10, 5}